When simplifying the quadratic formula to solve the equation x^2+6x-55=0, the number under the radical sign will be:A)-184B)232C)256
Mathematics · Middle School · Tue Nov 03 2020
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Given the equation:
x^2 + 6x - 55 = 0
a = 1
b = 6
c = -55
Simplify the quadratic equation, and determine the number under the radical sign.
Solution:
The Quadratic formula:
x = −b ± √(b^2 − 4ac)/2a
is used to solve quadratic equations where a ≠ 0, in the form
ax^2+bx+c=0
When b^2−4ac=0 there is one real root.
When b^2−4ac>0 there are two real roots.
When b^2−4ac<0 there are no real roots, only a complex number.
Substitute the given values of a, b and c to the quadratic formula.
x = −b ± √(b^2 − 4ac)/2a
x = −(6) ± √((6)^2 − 4(1)(-55))/2(1)
x = −6 ± √(36 + 220)/2
x = −6 ± √(256)/2
The number inside the radical sign is 256.
Final answer:
c. 256