What will be the value of EAX when the following sequence of instructions has executed? a. push 5.b. push 10.c. push 20.d. pop eax.
Computers and Technology · College · Sun Jan 24 2021
Answered on
a. `push 5` - This instruction places the value 5 on the top of the stack.
b. `push 10` - This instruction places the value 10 on top of the previously pushed value, so now 10 is at the top of the stack, with 5 just below it.
c. `push 20` - Following that, the value 20 is pushed onto the stack, making it the current top value, with 10 below it and 5 below that.
The stack is a Last-In-First-Out (LIFO) structure, which means that the last value that was pushed onto the stack will be the first one to be popped off.
d. `pop eax` - This instruction removes the value from the top of the stack and places it into the EAX register. Since 20 was the last value pushed, it will be the one to be popped off the stack and loaded into EAX.