What is the vertex of the parabola of the equation? y=-x^2+12x-4Step by step, please
Mathematics · College · Tue Nov 03 2020
Answered on
For finding the various parabola we know that the general vertex form of a parabola is y=m(x−a)^2+b where the vertex is (a, b). So the given equation is
y=-x^2+12x-4
y=(-1)(x^2-12x)-4, by adding (12/2)^2and substrate (12/2)^2 for making a square formula
y=(-1)(x^2-12x+ (6)^2-(6)^2)-4
y=(-1)[(x+6)^2 +36-4]
y=(-1)[(x+6)^2 +32]………(1)
By comparing equation(1) with the general equation y=m(x−a)^2+b
We get the vertices ( 6,32) answer.