What is the value of 3-6(z-2)(z-2)(z-2)
Mathematics · Middle School · Mon Jan 18 2021
Answered on
Given the numerical equation:
3-6(z-2)(z-2)(z-2)
Determine the value.
Solution:
In order to determine the value of the given numerical equation, we simply need to simplify first the values inside the parenthesis. To do so we can square the two (z-2), then later on apply the FOIL Method on the remaining.
= (z - 2)(z - 2)
= z^2 - 4z + 4
= (z^2 - 4z + 4)(z - 2)
= (z)(z^2)
= z^3
= (z)(-4z)
= -4z^2
=(z)(4)
= 4z
=(-2)(z^2)
= -2z^2
=(-2)(-4z)
= 8z
= (-2)(4)
= -8
=z^3 - 4z^2 + 4z - 2z^2 + 8z - 8
= z^3 -6z^2 + 12z - 8
Equate back to the original equation.
= 3 - 6( z^3 -6z^2 + 12z - 8)
= 3 - 6z^3 - 36z^2 + 72z - 48
= - 6z^3 - 36z^2 + 72z - 45
Final answer:
= - 6z^3 - 36z^2 + 72z - 45