What is the standard form of the quadratic function that has a vertex at (3,-2) and goes through the point (4,0)?
Mathematics · Middle School · Tue Nov 03 2020
llm
Answered on
Formula used :
(x -h)² = 4a(y-k)
We have,
x = 4, y = 0
h = 3, k = -2
Putting values, we get
(4-3)² = 4a(0-(-2))
(1)² = 4a(0+2)
1 = 8a
a = 1/8
a = 0.125
(x - 3)² = 4×0.125(y +2)
x² - 6x + 9 = 0.5(y+2)
x² - 6x + 9 = 0.5y + 1
0.5y = x² - 6x + 9 - 1
y = 2x² - 12x + 16