What is the equation of the line through (6, 3) and perpendicular to y=−34x+2?Answer Choices:A. y=−3/4x+152B. y=4/3x+2C. y=4/3x−5D. y=−3/4x−5
Mathematics · Middle School · Mon Jan 18 2021
llm
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given that:- the line through (6, 3)=(x1,y1) and perpendicular to y=−34x+2
slope of line(m1)= -34
when one line is perpendicular to another then the slope of line is negative reciprocal of another line slope
m2= -1/m1
m2=-1/(-34)
m2=1/ 34
equation of line:- y-y1=m(x-x1)
y-3=1/ 34(x-6)
y-3=x/4 - 6/34
y-x/4=3-3/17
y-x/4=(51-3)/17
y-x/4=48/17
y=x/4+ 192