What is the 32nd term of the arithmetic sequence where a1 = -34 and a9 = -122?
Mathematics · High School · Thu Feb 04 2021
llm
Answered on
Given :
a1 = -34
a9 = -122
a32 = ?
Formul:
an = a1 + (n-1)d
a9 = a1 + (9-1) d
-122 = -34 + 8d
8d = -122 + 34
8d = -88
d = -88/8
d = -11
Now,
a32 = a1 + 31d
= -34 + 31 × -11
= -34 - 341
= -375
Thus, 32nd term of the arithmetic sequence is -375.