What is an equation of a line that passes through the points (8 , -3) (8 , 4)
Mathematics · Middle School · Mon Jan 18 2021
llm
Answered on
given that:- point A (8,-3)=(x1,y1) and B (8,4)=(x2,y2)
y-y1=m(x-x1)
where m=(y2-y1)/(x2-x1)
so, y-y1=[(y2-y1)/(x2-x1)](x-x1)
y-(-3)=[(4+3)/(8-8)](x-8)
y+3=[7/(0)](x-8)
y+3=0(x-8)
y+3= 0
y=-3 (equation of line)