what are the solutions to the quadratic equation x^2-16=0
Mathematics · High School · Tue Nov 03 2020
llm
Answered on
In order to solve this equation, we can follow a simple formula: (a^2 - b^2) = (a-b)(a+b)
In our case:
a^2=x^2
b^2=16
Lets find b as the square root of 16.
Sqrt of 16= 4.
Sqrt of X^2= x
So if we substitute them in our formula we will have:
(a^2 - b^2) = (a-b)(a+b)=0
(x-4)(x+4)=0
First scenario:
x-4=0
x=4
Second scenario:
x+4=0
x=-4