What are the solutions to the equationx^2+14x=-130please do a step by step

Given the quadratic function:

 x^2 + 14x = -130
can be written as,
x^2 + 14x + 130 = 0

a = 1

b = 14

c= 130

Find the solution:

Solution:
In order to solve for the roots or the solutions of the equation, we simply must look at the 2nd and 3rd value. First we must think of two numbers that when added, the answer is 14, and when multiplied, the answer is 130. Hence, if we are unable to find the number, we will use the quadratic formula.

The Quadratic formula:

x = −b ± √(b^2 − 4ac)/2a

is used to solve quadratic equations where a ≠ 0, in the form
ax^2+bx+c=0

When b^2−4ac=0 there is one real root.

When b^2−4ac>0 there are two real roots.

When b^2−4ac<0 there are no real roots, only a complex number.

Substitute the given values of a, b and c to the quadratic formula.

x = −b ± √(b^2 − 4ac)/2a

x = −(3) ± √((14)^2 − 4(1)(130))/2(1)

x = −3 ± √(196 -  520)/2

x = −3 ± √(-324)/2

Since we have a negative value inside the radical sign, this means that we do not have any real solutions, due to the fact that we cannot take the square root of a negative number. Taking the square root of a negative number, will result to a complex number or an imaginary number.

Final answer:

No solution