The vertices of ΔXYZ are X(−3, −6), Y(21, −6), and Z(21, 4). What is the perimeter of the triangle?
Mathematics · High School · Tue Nov 03 2020
Answered on
X(−3, −6), Y(21, −6), and Z(21, 4)
D(distance)= root of (x2-x1)^2 + (y2-y1)^2
X=(-3,-6)=(x1,y1), Y=(21,-6)=(x2,y2)
XY=root of (21+3)^2 + (-6+6)^2
=root of (24)^2+0
=24
Y=(21,-6)=(x1,y1), Z=(21,4)=(x2,y2)
YZ=root of (21-21)^2 + (4+6)^2
=root of 0+(10)^2
=10
X=(-3,-6)=(x1,y1), Z=(21,4)=(x2,y2)
XZ=root of (21+3)^2 + (4+6)^2
=root of (24)^2+(10)^2
=root of 576+100
=root of 676
=26
perimeter of triangle= XY+YZ+XZ
=24+10+26
=60 (Answer)