The vertex form of the equation of a parabola is x=8(y-1)^2-15. What is the standard form of the equation?
Mathematics · High School · Mon Jan 18 2021
Answered on
Given:
x = 8 (y - 1)^2 - 15
Write in standard equation.
Solution:
Transpose first -15 to the other side of the equation, hence it must be taken to note that in transposing a number, the sign changes.
x = 8 (y - 1)^2 - 15
x + 15 = 8 (y - 1)^2
Divide both sides by 8 to cancel out 8(y-1)^2.
(x + 5)/8 = 8(y - 1)^2 / 8
(x + 5)/8 = (y - 1)^2
Take the square root of both sides.
((x + 5)/8)^½ = ((y - 1)^2 )^½
((x + 5)/8)^½ = y - 1
Now we simply need to transpose again-1 to the other side of the equation, leaving behind the value of y.
y = ((x + 5)/8)^½ + 1
Final answer:
y = ((x + 5)/8)^½ + 1