The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for each flower. The October price was a 20% increase of the September price. Part A What was the price of the flowers in September? Enter your answer in the box. $ Part B The seventh-grade class earned 40% of the selling price of each flower. In September, they sold 900 flowers. In October, they sold 700 flowers. Select a choice from each drop-down menu to make a true statement. The seventh-grade class earned more money in

Part A:

To determine the price of flowers in September, we need to find the original price before the 20% increase that led to the October price. First, let's find what 20% of the original price is, since this is the amount by which the price increased.

Assuming the original price is P dollars, a 20% increase would be 0.20P. This increase resulted in the October price, which is $1.50.

So, we can say that: Original Price + Increase (20% of Original Price) = October Price P + 0.20P = $1.50

Combining like terms gives us: 1.20P = $1.50

Now, we can solve for P to find the original price: P = $1.50 / 1.20 P = $1.25

The price of flowers in September was $1.25.

Part B:

The seventh-grade class earns 40% of the selling price of each flower.

In September: The selling price for each flower was $1.25. 40% of the price of each flower is 0.40 * $1.25 = $0.50. They sold 900 flowers, so they earned 900 * $0.50 = $450.

In October: The selling price for each flower was $1.50. 40% of the price of each flower is 0.40 * $1.50 = $0.60. They sold 700 flowers, so they earned 700 * $0.60 = $420.

Comparing the totals, the seventh-grade class earned more money in September ($450) than in October ($420).