The smallest natural number divisible by three different primes is
Mathematics · College · Thu Feb 04 2021
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To find the smallest natural number divisible by three different primes, we multiply the smallest three prime numbers together.
Prime numbers are numbers greater than 1 that have only two factors, which are 1 and themselves. The first three prime numbers are:
2, 3, 5
When we multiply these three numbers together, we get:
2 * 3 * 5 = 30
So, the smallest natural number divisible by three different prime numbers is 30.