The height of a helicopter above the ground is given by h=3.00t3, where h is in meters and t is in seconds. After 2.00 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?S
Mathematics · College · Tue Nov 03 2020
Answered on
Given:
Height of the helicopter above the ground:
h = 3.00t^3
h = height in meters
t = time in seconds
Determine how long does the mailbag reach the ground when it is realesed from the helicopter after 2 seconds.
Solution:
Substitute 2 as the value of t in the given equation for h in order to determine the height of the helicopter.
h = 3(2)^3
h = 24 m
In order to determine the time, we divide the height by acceleration due to gravity.
t^2 = 24m/9.8m/s^2
t^2 = 2.44 s^2
Take the square root of both sides in order to determine the value of t.
t = 1.56 s
Final answer:
The mailbag will hit the ground after 1.56 s