The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is
Mathematics · Middle School · Tue Nov 03 2020
Answered on
Given:
Center (4,0)
Radius 2√(3)
Determine the equation of the circle.
Solution:
The equation of the circle comes in two forms mainly,
Equation of the circle with center at the origin (0,0)
x^2 + y^2 = r^2
Equation of the circle with the center at any points (h,k)
(x - h)^2 + (y - k)^2 = r^2
Since we are given a point then we will use the second equation.
(x - 4)^2 + y^2 =(2√(3))^2
(x - 4)^2 + y^2 =(4)(3)
(x - 4)^2 + y^2 =12
Final answer:
Equation of the circle: (x - 4)^2 + y^2 =12