The cashier counted 86 bills of 5s and 20s at the end of the shift. If the total value was 1,105 how many of each denomination did she have

llm

Answered on Tue Oct 18 2022

Given :

Total value = 1,105

Total bills = 86

Let the number of 5s be x

And, number of 20s be y

Then, according to question

5x + 20y = 1105 …1

x + y = 86 ...2

Using elimination method:

Multiplying equation 2 by 5, we get

5x + 5y = 430 …3

Subtracting equation 3 from 1, we get

5x + 20y - 5x - 5y = 1105 - 430

15y = 675

y = 675/15

y = 45

Now, putting value of y in equation 2, we get

x + 45 = 86

x = 86 - 45

x = 41

Hence, she has 41 5s and 45 20s .