Solve Systems by Substitution x+y=-1 3x-2y=2 and x=y-2 3x-4y=-13

llm

Answered on Fri Nov 04 2022

We have,

x+y=-1 …1

3x-2y=2 …2

From equation 2

3x = 2 + 2y

x = (2 + 2y)/3

Puttinga value in equation 1

(2 + 2y)/3 + y = - 1

2 + 2y + 3y = - 3

5y = -3 - 2

y = -5/5

y = -1

Now, putting value of y in equation 1

so,

x - 1 = -1

x = - 1 + 1

x = 0

And,

x=y-2 .. 3

3x-4y=-13 …4

Putting value of equation 3 in 4, we get

3(y -2) - 4y = - 13

3y - 6 - 4y = -13

-y - 6 = - 13

y = 13 - 6

y = 7

Putting value of y in equation 1, we get

x = 7 - 2

y = 5