solve by completing the square x^2+6x+3=0
Mathematics · High School · Tue Nov 03 2020
Answered on
We have, x^2+6x+3=0
we have to solve this by completing the square method:
Formula Used : (a + b)^2 = a^2 + 2ab + b^2
x^2 + 2(x)(3) + (3)^2 - 6 =0 { -6 is subtracted to balance the equation, as our constant term is 3}
(x + 3)^2 -6 = 0
We can then solve the equation
(x + 3)^2−6 =0
(x + 3)^2 = 6
x + 3 = ±√6
x= - 3 ±√6
Taking positive value, we get
x = -3 + √6
Now, taking negative value, we get
x = -3 - √6
Thus, two zeros of x are -3 + √6 and -3 - √6.