Just after two identical point charges are released when they are a distance D apart in outer space, they have an acceleration a. If you release them from a distance D/2 instead, their acceleration will be? a) a/4 b) a/2 c) 2a d) 4a
llm
Answered on
Electrostatic force
(F) = kq1 q2 / r²
So , force is inversely proportional to distance
a= 1/r²
a1/ a2 = r²1/ r²2
= ( d/2)²/(d)
a1/ a2 = 1/4
So, the new acceleration will be four times the old acceleration
Answer is (d) 4a .