Joey has $5.75 made up of all dimes and quarters. If Joey has 38 coins, how many of each coin does he have?

llm

Answered on Tue May 31 2022

Let the number of dimes be x

And, number of quarters be y

Then, x + y = 38 …1

0.10x + 0.25y = 5.75

Multiplying by 100

10x + 25y = 575 …2

Now, Multiplying equation 1 by 10

10x + 10y = 380 …3

Subtracting 3 from 2, we get

10x + 25y - 10x - 10y = 575 - 380

15y = 195

y = 195/15

y = 13

Now, putting value of y in equation 1

x + 13 = 38

x = 38 - 13

x = 25

Hence, there are 25 dimes and 13 quarters.