If (-6,-38) and (5,28) are two anchor points on the trend line, then find the equation of the line. Please help me!!
Mathematics · Middle School · Tue Nov 03 2020
Answered on
Given the points:
(-6, -38)
(5, -28)
x1= -6
x2 = 5
y1 =-38
y2= 28
Find the equation of the line.
The equation of the line can be written in point-slope form:
Point-slope form:
y - y1 =m(x -x1)
Solution:
Before we can write in point-slope form, we must first find the slope of the line, we can find the slope by using the slope formula.
m = y2 -y1 /x2 -x1
m= (28 - (-38))/(5 - (-6))
m= (28 + 38) / (5 + 6)
m = 66/11
m =11
Substitute the given values of x1, m and y1 to the formula for the point-slope form.
y - (-38) =11 ( x - (-6))
y + 38 = 11 (x + 6)
Final answer:
y + 38 = 11 (x + 6)