Help me out here plz? i'll name u brainliest Factor completely 2x^3 + 14x^2 + 4x + 28 A) 2(x3 + 7x2 + 2x + 14) B) (2x + 14)(x2 + 2) C) 2[(x + 7)(x2 + 2)] D) (x + 7)(2x2 + 4)
Mathematics · Middle School · Thu Feb 04 2021
Answered on
The expression you’re asking to factor completely is 2x^3 + 14x^2 + 4x + 28.
To do this, look for a common factor in all terms first. Here, you can see that each term shares a factor of 2. Factoring out the 2 gives:
2(x^3 + 7x^2 + 2x + 14)
Next, look to see if the expression within the parentheses can be factored further. In the parentheses, there is x^3 + 7x^2 + 2x + 14. You can try factoring by grouping, which involves grouping terms to see if they share a common factor.
However, x^3 + 7x^2 + 2x + 14 does not factor easily through grouping or other factoring methods and there are no common binomial factors, thus it’s already in its simplest form.
So the correct answer is A) 2(x^3 + 7x^2 + 2x + 14). The other options involve incorrect factoring or break down the terms incorrectly.