Given that the points (-1, 6), (3, 6), (3, 1), and (-1, 1) are vertices of a rectangle, how much shorter is the width than the length?
Mathematics · College · Tue Nov 03 2020
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Given that the points (-1, 6), (3, 6), (3, 1), and (-1, 1) are vertices of a rectangle,
Let's take A(-1,6), B(3,6), C(3,1), and D(-1,1)
using the distance formula of the rectangle for length
AB=√[(3-(-1))^2+(6-6)^2]=√(4)=2 unit
For width
BC=√[(3-3)^2+(1-6)^2]=√(5)^2=5unit
The difference between width and length is BC-AB=5-4=1 then the width than the length is shorter than 1 unit.