Given h(t)=-2(t+5)^2+4, find h(-8) -334 -14 -45 -445

Given:

h(t)=-2(t+5)^2+4

Find h(-8), -334, -14, -45, -445

Solution:

Substitute the values of t in the given function.

h(-8)=-2(-8+5)^2+4

h(-8)=-2(-3)^2+4

h(-8)=-2(9)+4

h(-8)=-18 +4

h(-8) = -14

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h(-334)=-2(-334+5)^2+4

h(-334)=-2(-329)^2+4

h(-334)=-2(108,241)+4

h(-334)=-216,482+4

h(-334)=-216,478

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h(-14)=-2(-14+5)^2+4

h(-14)=-2(-9)^2+4

h(-14)=-2(81)+4

h(-14)=--162+4

h(-14)= -158

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h(-45)=-2(-45+5)^2+4

h(-45)=-2(-40)^2+4

h(-45)=-2(1600)+4

h(-45)=-3200+4

h(-45)= -3196

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h(-445)=-2(-445+5)^2+4

h(-445)=-2(-440)^2+4

h(-445)=-2(193600)+4

h(-445)=-387,200+4

h(-445)= -387,196