give the genotype of the offspring produced when an albino male Marriesfemale who is heterozygous for albinism.​

To predict the genotype of offspring from a cross, we can use a Punnett square. In this case, we are dealing with albinism, which is commonly caused by a recessive allele. Let's denote the recessive allele for albinism as "a" and the dominant normal pigmentation allele as "A".

If the male is albino, that means he has the genotype "aa" (because albinism is recessive, an individual must have two copies of the recessive allele to express the trait).

A female who is heterozygous for albinism has one copy of the recessive allele and one copy of the dominant allele, and her genotype is "Aa".

When you set up the Punnett square for this cross, you put the male's alleles on the top and the female's alleles on the side (or vice versa), like so:

``` a a A Aa Aa a aa aa ```

As the Punnett square shows, there are four possible genotypes for the offspring:

1. "Aa" - This child has normal pigmentation but is a carrier of the albinism trait. 2. "Aa" - As with the first, this child also has normal pigmentation but is a carrier. 3. "aa" - This child is albino, expressing the trait. 4. "aa" - Like the third child, this one is also albino.

So, 50% of the children (2 out of 4) would be expected to be carriers with a heterozygous genotype ("Aa"), and the other 50% would be albino with the homozygous recessive genotype ("aa").