find three consecutive integers whose sum is six times the greater integer

llm

Answered on Sat Apr 02 2022

Let the first integer be x

then, 2nd integer is x+1

and, 3rd integer is x+2

So, According to question

x + x+1+x+2 = 6(x+2)

3x + 3= 6x + 12

transposing 3x and 12 to other sides, we get

6x - 3x = 3 -12

3x = -9

x = -9/3

x = -3

So, the integers are -3, -2 and -1