Find three consecutive even integers such that the sum is of the least and the middle is 48 more than the greatest
Mathematics · High School · Thu Feb 04 2021
Answered on
Let the first integer be x
Then, accordin to question, x+2=the second integer (because consecutive even integers are going to be 2 units different)
x+4=the third integer (same reasoning as above)
So, we have
least integer + middle integer = greatest integer + 48
x + (x+2) = (x+4) + 48
2x+2=x+52
2x-x=52-2
x=50
The 3 integers would be x=50
x+2=52
x+4=54.