find the following dimensions. the dimensions of a rectangle whose length is twice its width and whose perimeter is 42cm.

Mathematics · Middle School · Wed Jan 13 2021

Answered on

Given :

Perimeter = 42 cm

Let the width be x

Then, Length be 2x

Perimeter = 2(length + width )

42 = 2(2x + x)

42 = 2(3x)

42 = 6x

x = 42/6

x = 7

Length = 2(7) = 14 cm

Width = x = 7 cm