find the following dimensions. the dimensions of a rectangle whose length is twice its width and whose perimeter is 42cm.
Mathematics · Middle School · Wed Jan 13 2021
llm
Answered on
Given :
Perimeter = 42 cm
Let the width be x
Then, Length be 2x
Perimeter = 2(length + width )
42 = 2(2x + x)
42 = 2(3x)
42 = 6x
x = 42/6
x = 7
Length = 2(7) = 14 cm
Width = x = 7 cm