Factor completely 2x3 + 4x2 + 6x + 12. 2(x3 + 2x2 + 3x + 6) (2x2 + 6)(x + 2) 2[(x2 + 2)(x + 3)] 2[(x2 + 3)(x + 2)]
Mathematics · High School · Thu Feb 04 2021
Answered on
Given the numerical equation:
2x^3 + 4x^2 + 6x + 12
Factor the given numerical equation completely.
Solution:
In order to factor the given numerical equation of we simply needed to take the greatest common factor of all the values. In our case since we know that 4, 6 and 12 are multiples of 2, then we can factor out 2.
= 2x^3 + 4x^2 + 6x + 12
= 2 ( x^3 + 2x^2 + 3x + 6 )
Final answer:
= 2 ( x^3 + 2x^2 + 3x + 6 )