Factor 25m^100 − 121n^16 1. (5m^50 - 11n^8)^2 2. (5m^10 - 11n^4) (5m^10 + 11n^4) 3. (5m^50 - 11n^8) (5m^50 + 11n^8) 4. (5m^10 - 11n^4)^2
Mathematics · College · Sun Jan 24 2021
llm
Answered on
We have,
25m^100 − 121n^16
It can be written as
(5m⁵⁰)² - (11n⁸)²
Formula :
(a)² - (b)² = (a + b) (a - b)
So,
(5m⁵⁰)² - (11n⁸)² = (5m⁵⁰ + 11n⁸) (5m⁵⁰ - 11n⁸)
Hence, option (3) is correct.