An auditorium has 28 seats in the front row. Each row behind the front has 3 more seats than the row directly in front of it. How many seats are there in the 11th row?
Mathematics · Middle School · Thu Feb 04 2021
llm
Answered on
Formula Used:
a_n = a + (n-1)d
We have, a = 28, d = 3 and n =11
Substituting values in formula, we get
a_11 = 28 + (11-1) 3
= 28 + 10 × 3
= 28 + 30
= 58
Hence, there will be 58 seats in 11th row.