Aman tosses a jart upward with a velocity of 14.1 m/s a 60° angle

It seems like your question might be incomplete. However, based on what you've provided, I can explain the situation of Aman tossing a javelin at an angle.

Answer: When Aman tosses the javelin upward at a 60° angle with an initial velocity of 14.1 m/s, the motion of the javelin can be analyzed using the principles of projectile motion.

In projectile motion, we consider two components of the motion – the horizontal component and the vertical component. These components are independent of each other, meaning that the horizontal motion does not affect the vertical motion and vice versa.

To calculate these components, we use the initial velocity and the angle of projection. We can find the initial horizontal velocity (Vx) and the initial vertical velocity (Vy) by using trigonometric functions:

1. The horizontal component of velocity (Vx) is calculated using the cosine function: Vx = V * cos(θ) 2. The vertical component of velocity (Vy) is calculated using the sine function: Vy = V * sin(θ)

Here, V is the initial velocity, and θ is the angle of projection.

For Aman's javelin: - Initial velocity (V) = 14.1 m/s - Angle of projection (θ) = 60°

Vx = 14.1 m/s * cos(60°) = 14.1 m/s * 0.5 ≈ 7.05 m/s Vy = 14.1 m/s * sin(60°) = 14.1 m/s * (√3/2) ≈ 12.2 m/s

With these velocities, we can now analyze the javelin's motion:

- The horizontal distance (range) can be found using the time of flight and the horizontal velocity. - The maximum height can be calculated using the vertical velocity and the acceleration due to gravity (9.81 m/s² downward).

If you had a specific question related to Aman's javelin throw, such as how far it goes or how high it rises, please provide additional information so I can assist you further.