A rectangle has twice the area of a square. The rectangle is 8 in. by 4 in. What is the perimeter of the square?

According to the question , Area of Rectangle is twice of area of Square it means,

Area of Rectangle = Area of Square*2

Length*Breath= (Side*side)2

it is given that Length= 8 in.

                           Breath=4 in.

put there values in the formula

8*4=(Side^2)2

32=(side^2)2

32/2=side^2

16=side^2

side=square root of 16

side=4       (side of square)

Now, perimeter of square = 4*side

          perimeter of square =4*4

          perimeter of square  =16 in

Given : Rectangle has twice the area of a square

 length of rectangle = 8 in.

breadth of rectangle = 4 in.

Area of rectangle = length * breadth

                               = 8 in * 4 in.

                               = 32 in.^2

Area of Square = Area of rectangle / 2         (according to question)

                            = 32/2

                            = 16 in.^2

Area of square = (side)^2

             (side)^2 = 16 in.^2

                    side = √16 in.^2

                    side = 4 in.

Perimeter of square = 4 * side

                                    = 4 * 4 in.

                                    = 16 in. 

Therefore, perimeter of square is 16 in.