A pump lifts water from a lake to a large tank 20 m above the lake. How much work against gravity does the pump do as it transfers 5.0 m^3 if the density is ?=1000kg/m^3?
llm
Answered on
Given the statement:
A pump lifts water from a lake to a large tank 20 m above the lake.
Determine how much work does the pump does as it transfers 5.0 m^3 if the density is 1000 kg/m^3.
Formula for work:
w = Fd
w = work
F= force
d = displacement
Formula for density:
d = m/v
Solution:
Solve first for the mass of the then solve for the work.
d = m/v
m = dv
m = (5.0 m^3) (1000 kg/m^3)
m = 5000 kg
Now we equate the mass to force by multiplying 9.8 m/s^2
F = (5000 kg)(9.8 m/s^2)
F= 49,000 N
Solve for w.
W = (49000 N)(20 m)
W = 980,000 J
Final answer:
W = 980,000 J