A missile is fired from a jet flying horizontally at Mach 1 (1100 ft/s). The missile has a horizontal acceleration of 1000 ft/s2. Calculate its horizontal velocity at 10.0 seconds after it is fired. (Assume constant acceleration of the missile throughout its flight.)

To calculate the missile's horizontal velocity at 10.0 seconds after it is fired, we apply the basic kinematic equation for uniform acceleration:

\( v = u + at \)

where: - \( v \) is the final velocity we want to find, - \( u \) is the initial velocity (the velocity of the jet, since the missile is fired from the jet), - \( a \) is the acceleration of the missile, - \( t \) is the time after the missile is fired.

We have: - Initial velocity \( u \) = 1100 ft/s (since the jet is moving at Mach 1), - Acceleration \( a \) = 1000 ft/s² (given), - Time \( t \) = 10.0 s.

Now, we calculate:

\( v = u + at \) \( v = 1100 \, \text{ft/s} + (1000 \, \text{ft/s}^2)(10.0 \, \text{s}) \) \( v = 1100 \, \text{ft/s} + 10000 \, \text{ft/s} \) \( v = 11100 \, \text{ft/s} \)

So, the horizontal velocity of the missile at 10.0 seconds after it is fired is 11100 ft/s.