A cube is packed with decorative pebbles. If the cube has a side length of 6 inches, and each pebble weighs on average 0.5 lb per cubic inch, what is the total weight of the pebbles in the cube?

Mathematics · College · Tue Nov 03 2020

Answered on

To solve for the total weight of the pebbles in the cube, multiply the volume of the cube by the average weight of pebbles per square inch. To find the volume of the cube. multiply the length, width and height of the cube. Since the cube has 6 equal faces/squares, the formula can be represented as v = a* a* a or a³; where a is the side of the cube. To solve for the volume of the container, substitute the given length 6 inches. 
> v =a³
> v = 6³
> v = 216 or 216in³
The volume of the cube is 216in³.
Now, multiply 216in³ by 0.5 lb per cubic inch
>216 in³ * 0.5 lb/in³
>216 * 0.5 lb
> 108 lb.
The total weight of pebbles in the cube is 108 lb.

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