A cooler contains 8 cans of soda; 2 colas, 5 orange, and 1 cherry. Two cans are selected at random without replacement. Find the probability that at least one can is orange
Mathematics · College · Mon Jan 18 2021
Answered on
Given :
Cans of soda = 8
Cans of colas = 2
Cans of orange = 5
Cans of cherry = 1
Total = 8 + 2 + 5 + 1
= 16
So, probability = Favorable outcome/Total outcome
Probability of 1st can being orange = 5/16
If 1st is not orange then, probability of 2nd being orange = 5/15
= 1/ 3
Probability of atleast 1 orange can = 5/16 + 1/ 3
= (15 + 16)/48
= 31/ 48
Hence, probability of at least one can being orange is 31/ 48.