A Computer randomly generates an integer from 1-10. Find the Probability of the given event. Write your answer as a percent. 1. P(5) 2.P(odd Number) P(factor of 20)

To find the probability of an event, you can use the formula:

\[ P(\text{Event}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \]

In this case, since the computer generates an integer from 1 to 10:

1. P(5):

  - There is only one favorable outcome (getting a 5).

  - There are 10 possible outcomes (numbers from 1 to 10).

  - \( P(5) = \frac{1}{10} = 0.1 \).

2. P(Odd Number):

  - There are 5 favorable outcomes (1, 3, 5, 7, 9).

  - There are 10 possible outcomes.

  - \( P(\text{Odd Number}) = \frac{5}{10} = 0.5 \).

3. P(Factor of 20):

  - The factors of 20 are 1, 2, 4, 5, 10, and 20.

  - There are 6 favorable outcomes.

  - There are 10 possible outcomes.

  - \( P(\text{Factor of 20}) = \frac{6}{10} = 0.6 \).

Now, to express these probabilities as percentages, you multiply each probability by 100:

1. \( P(5) = 0.1 \times 100\% = 10\% \)

2. \( P(\text{Odd Number}) = 0.5 \times 100\% = 50\% \)

3. \( P(\text{Factor of 20}) = 0.6 \times 100\% = 60\% \)

So, the probabilities as percentages are 10%, 50%, and 60%, respectively.