A child in a swing oscillates with a certain frequency of oscillation (the child is sitting still. another child sits next to the first child. how does the swing’s frequency of oscillation change when the second child sits next to the first child?
Physics · High School · Thu Feb 04 2021
Answered on
Let's assume child in a swing with a simple pendulum.
The time period of which is given by the formula T=2π√(l/g)
Where ,
l = the length from the starting point of the rope till the child's centre of mass.
g = acceleration due to gravity.
Now, when the child stands up, the centre of mass moves upwards, resulting in the decrease in the value of l .
So , by that time period of the swinging child decreases.