A 1.5m wire carries a 2 A current when a potential difference of 59 V is applied. What is the resistance of the wire?
Physics · High School · Thu Feb 04 2021
Answered on
You can use Ohm's Law to calculate the resistance of the wire. Ohm's Law is given by the formula
R=IV
where:
- R is the resistance,
- V is the potential difference (voltage), and
- I is the current.
In your case:
- �=59
- V=59 volts
- v=2
- I=2 amperes
Now, substitute these values into the formula:
v=592
R=2
59
v=29.5 Ω
R=29.5Ω
So, the resistance of the wire is 29.5
29.5 ohms.
You can use Ohm's Law to calculate the resistance of the wire. Ohm's Law is given by the formula:
R=IV
where:
R is the resistance,
- V is the potential difference (voltage), and
- I is the current.
In your case:
v=59
- V=59 volts
- v=2
- I=2 amperes
Now, substitute these values into the formula:
v=592
R=2
59
v=29.5 Ω
R=29.5Ω
So, the resistance of the wire is 29.5
29.5 ohms.