6x^3 - 9x^2 + 4x - 6
Mathematics · High School · Thu Feb 04 2021
llm
Answered on
We have, 6x^3 - 9x^2 + 4x - 6 = 0
Solving by taking common
3x^2(2x - 3) + 2(2x - 3) = 0
(3x^2 + 2) (2x - 3) = 0
So, 3x^2 + 2 = 0
3x^2 = -2
x^2 = -2/3
x^2= 2/3i^2 {i^2 = -1}
x = ±√2/3 i
and 2x - 3 =0
2x = 3
x =3/2