3a+8+2ax≥3ax-4a what is a
Mathematics · College · Mon Jan 18 2021
Answered on
Given the numerical inequality:
3a + 8 + 2ax ≥ 3ax - 4a
Solve for a.
Solution:
In order to solve for a, we simply need to combine the similar terms in the numerical inequality. To do so, we transpose first -4a, and 8 + 2ax on the other side of the equation. Hence, we must take note that in transposing a number, the sign chagnes.
3a + 8 + 2ax ≥ 3ax - 4a
3a + 4a ≥ 3ax -2ax - 8
7a ≥ ax - 8
Divide both sides by 7 in order to cancel out 7a, leaving behind a.
7a /7 ≥ (ax - 8)/7
a ≥ 1/7ax - 8/7
Final answer:
a ≥ 1/7ax - 8/7