-(3/(2y+12))+2=-(8/(y+6)
Mathematics · Middle School · Mon Jan 18 2021
Answered on
Given the numerical equation:
-(3/(2y+12))+2=-(8/(y+6))
Simplify.
Solution:
In order to solve for y, we simply need to start by multiplying both sides by (2y + 12) and (y + 6). This will cancel out the values in the denominator.
(2y + 12 ) -(3/(2y+12))+2=-(8/(y+6)) (2y + 12)
-3 + 2(2y + 12) = -8(2y + 12)/(y + 6)
-3 + 4y + 24 = -16y - 96/(y + 6)
4y + 21 = -16y - 96/(y + 6)
Multiply both sides by y + 6
( y + 6) 4y + 21 = -16y - 96/(y + 6) (y + 6)
4y^2 + 21y + 24y + 126 = -16y - 96
4y^2 + 45y + 126 = -16y - 96
Transpose -16y and - 96 on the other side of the equation, hence it must be taken to note that in transposing numbers, the sign changes.
4y^2 + 45y + 126 + 16y + 96 = 0
4y^2 + 61y + 222 = 0
Final answer:
4y^2 + 61y + 222 = 0