3(2d −1)≥4(2d−3)−3 ) {d | d ≥ −9} b) {d | d ≤ −6} c) {d | d ≥ 3} d) {d | d ≤ 6}

Mathematics · High School · Sun Jan 24 2021

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Given the inequality:

3(2d −1) ≥ 4(2d−3)−3 )

Solve for the inequality.

Solution:

In order to solve for the inequality, simply distribute first 3 and 4 to their corresponding parenthesis.

3(2d −1) ≥ 4(2d−3)−3 )

6d −3) ≥ 4(2d 

6d −3 ≥ 8d

Transpose 6d to the other side of the equation hence it must be taken to note that in transposing a number, the sign changes.

−3 ≥ 8d - 6d

−3 ≥ 2d

DIvide both sides by 2 in order to determine the value of d.

−3/2 ≥ 2d/2

−3/2 ≥ d

Final answer:

−3/2 ≥ d

 

 

 

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