1/8 (16k-24)+1/5 (2+10k)
Mathematics · High School · Tue Nov 03 2020
Answered on
this expression 1/8 (16k-24)+1/5 (2+10k) can be expressed in this way
[(16k-24)/8]+[(2+10k)/5]
to solve this expression they both should have the same denominator, and to find that we need to find the smallest multiply of those numbers
that is 40 which is going to be our new denominator
in order to do that, the first fraction will be multiplied with 5 and the second one with 8
5[(16k-24)/8]+8[(2+10k)/5]=
[(80k-120)/40]+[(16+80k)/40]=
since we have the same denominator, we can substract the numerators
[(80k-120)-(16+80k)]/40=
(80k-120-16+80k)/40=
(160k-136)/40 we will equal it with 0 so we can find a value for k
(160k-136)/40=0
160k-136=40*0
160k-136=0
160k=136
k=136/160=34/40=17/20