16 - 2r = -3r + 6r +1 TE
Mathematics · Middle School · Thu Feb 04 2021
Answered on
Given the numerical equation:
16 - 2r = -3r + 6r + 1
Solve for r.
Solution:
In order to solve for r, we simply need to combine similar terms first.
16 - 2r = -3r + 6r + 1
16 - 2r = 3r + 1
Transpose -2r and 1 to the opposiste sides of the equation, hence we must take note that in transposing a number, the sign changes.
16 -1 = 3r + 2r
15 = 5r
Divide both sides by 5 in order to cancel out 5r, leaving behind r.
5r/5 = 15/5
r = 3
Final answer:
r = 3