1) 2 (x+3) +3 (5-x)= 2) 3 (y+2) -4y=-24y 3) -(x+2) -2(1-x)= 4) - x? +5x + x2=1 What the answer

Solve the following numerical expression:

1) 2 (x+3) +3 (5-x)=

Distribute the values of 2 and 3 on the parenthesis and combine like terms.

=2x + 6 + 15 - 3x

= -x + 21

x = 21

2) 3 (y+2) -4y=-24y

Distribute 3 on the values inside the parenthesis and combine like terms.

 3y + 6 - 4y = -24y

-y + 6 = -24y

23y + 6 = 0

23y = -6

y = -6/23

3) -(x+2) -2(1-x)= 4

Distribute -2 on the values inside the parenthesis and combine like terms.

= -x -2 -2 + 2x -4

= x -8

x = 8

4) - x +5x + x^2=1

= x^2 + 5x -1

Solve using the quadratic formula

The Quadratic formula:

x = −b ± √(b^2 − 4ac)/2a

is used to solve quadratic equations where a ≠ 0, in the form
ax^2+bx+c=0

When b^2−4ac=0 there is one real root.

When b^2−4ac>0 there are two real roots.

When b^2−4ac<0 there are no real roots, only a complex number.

x = −5 ± √(5^2 − 4(1)(-1))/2(1)

x = −5 ± √(25 + 4)/2

x = −5 ± √(29)/2

x = −5 ± 5.38/2

 Solve for ± individually.

x = −5 + 5.38/2

x = .38/2

x = 0.19

x = −5 - 5.38/2

x= -10.38/2

x = -5.19