The perimeter of a rectangle is 48 feet The length is 10 feet longer than the width find the area of the rectangle

llm

Answered on Thu Apr 07 2022

Given:

Perimeter = 48 feet

Let width be x feet

Then, Length will be (x + 10) feet

We know, Perimeter = 2(l + w)

48 = 2(x +10 + x)

48 = 2(2x + 10)

48 = 4x + 20

4x = 48 - 20

4x = 28

x = 28/4

x= 7

So, width = 7 feet

And, Length = 7 + 10 = 17 feet

Area of rectangle = Length × width

Area = 17 × 7

Area = 119 feet²

Thus, Area of rectangle is 119 feet².